01Medium210×since 2002Q3412Let f:[0,∞)→[0,∞)f:[0,\infty ) \to [0,\infty )f:[0,∞)→[0,∞) be defined as f(x)=∫0x[y]dyf(x) = \int_0^x {[y]dy}f(x)=∫0x[y]dy where [x] is the greatest integer less than or equal to x. Which of the following is true?Af is continuous at every point in [0,∞)[0,\infty )[0,∞) and differentiable except at the integer points.Bf is both continuous and differentiable except at the integer points in [0,∞)[0,\infty )[0,∞).Cf is continuous everywhere except at the integer points in [0,∞)[0,\infty )[0,∞).Df is differentiable at every point in [0,∞)[0,\infty )[0,∞).Check answerSkip
02Medium210×since 2002Q3413If f(x) = \left\{ {\matrix{ {\int\limits_0^x {\left( {5 + \left| {1 - t} \right|} \right)dt,} } & {x > 2} \cr {5x + 1,} & {x \le 2} \cr } } \right., thenAf(x) is not continuous at x = 2Bf(x) is everywhere differentiableCf(x) is continuous but not differentiable at x = 2Df(x) is not differentiable at x = 1Check answerSkip
03Easy210×since 2002Q3414The value of the integral ∫−11log(x+x2+1)dx\int\limits_{ - 1}^1 {\log \left( {x + \sqrt {{x^2} + 1} } \right)dx}−1∫1log(x+x2+1)dx is :A2B0C−-−1D1Check answerSkip
04Medium210×since 2002Q3415The value of the definite integral ∫−π4π4dx(1+excosx)(sin4x+cos4x)\int\limits_{ - {\pi \over 4}}^{{\pi \over 4}} {{{dx} \over {(1 + {e^{x\cos x}})({{\sin }^4}x + {{\cos }^4}x)}}}−4π∫4π(1+excosx)(sin4x+cos4x)dx is equal to :A−π2- {\pi \over 2}−2πBπ22{\pi \over {2\sqrt 2 }}22πC−π4- {\pi \over 4}−4πDπ2{\pi \over {\sqrt 2 }}2πCheck answerSkip
05Hard210×since 2002Q3416The value of ∫−1212((x+1x−1)2+(x−1x+1)2−2)12dx\int\limits_{{{ - 1} \over {\sqrt 2 }}}^{{1 \over {\sqrt 2 }}} {{{\left( {{{\left( {{{x + 1} \over {x - 1}}} \right)}^2} + {{\left( {{{x - 1} \over {x + 1}}} \right)}^2} - 2} \right)}^{{1 \over 2}}}dx}2−1∫21((x−1x+1)2+(x+1x−1)2−2)21dx is :Alog_e 4Blog_e 16C2log_e 16D4log_e (3 + 22{\sqrt 2 }2)Check answerSkip
06Hard210×since 2002Q3417If the value of the integral ∫05x+[x]ex−[x]dx=αe−1+β\int\limits_0^5 {{{x + [x]} \over {{e^{x - [x]}}}}dx = \alpha {e^{ - 1}} + \beta }0∫5ex−[x]x+[x]dx=αe−1+β, where α\alphaα, β\betaβ ∈\in∈ R, 5α\alphaα + 6β\betaβ = 0, and [x] denotes the greatest integer less than or equal to x; then the value of (α\alphaα + β\betaβ)² is equal to :A100B25C16D36Check answerSkip
07Easy210×since 2002Q3418The value of ∫−π2π2(1+sin2x1+πsinx) dx\int\limits_{ - {\pi \over 2}}^{{\pi \over 2}} {\left( {{{1 + {{\sin }^2}x} \over {1 + {\pi ^{\sin x}}}}} \right)} \,dx−2π∫2π(1+πsinx1+sin2x)dx isAπ2{\pi \over 2}2πB5π4{{5\pi } \over 4}45πC3π4{{3\pi } \over 4}43πD3π2{{3\pi } \over 2}23πCheck answerSkip
08Medium210×since 2002Q3419∫616logex2logex2+loge(x2−44x+484)dx\int\limits_6^{16} {{{{{\log }_e}{x^2}} \over {{{\log }_e}{x^2} + {{\log }_e}({x^2} - 44x + 484)}}dx}6∫16logex2+loge(x2−44x+484)logex2dx is equal to :A6B8C5D10Check answerSkip
09Medium210×since 2002Q3420The value of the integral ∫01xdx(1+x)(1+3x)(3+x)\int\limits_0^1 {{{\sqrt x dx} \over {(1 + x)(1 + 3x)(3 + x)}}}0∫1(1+x)(1+3x)(3+x)xdx is :Aπ8(1−32){\pi \over 8}\left( {1 - {{\sqrt 3 } \over 2}} \right)8π(1−23)Bπ4(1−36){\pi \over 4}\left( {1 - {{\sqrt 3 } \over 6}} \right)4π(1−63)Cπ8(1−36){\pi \over 8}\left( {1 - {{\sqrt 3 } \over 6}} \right)8π(1−63)Dπ4(1−32){\pi \over 4}\left( {1 - {{\sqrt 3 } \over 2}} \right)4π(1−23)Check answerSkip
10Medium210×since 2002Q3421If [x] is the greatest integer ≤\le≤ x, then π2∫02(sinπx2)(x−[x])[x]dx{\pi ^2}\int\limits_0^2 {\left( {\sin {{\pi x} \over 2}} \right)(x - [x]} {)^{[x]}}dxπ20∫2(sin2πx)(x−[x])[x]dx is equal to :A2(π\piπ −-− 1)B4(π\piπ −-− 1)C4(π\piπ + 1)D2(π\piπ + 1)Check answerSkip